GMAT Exam  >  GMAT Questions  >  Set A: {-11, 0, 0, 11}Set B: {2, 4, 6, 8}Set ... Start Learning for Free
Set A: {-11, 0, 0, 11}
Set B: {2, 4, 6, 8}
Set C: {50, 51, 52, 53}
Set D: {12, 12, 12, 12}
Which of the following sets have a maximum & minimum standard deviation respectively?
  • a)
    Max: A, Min: B
  • b)
    Max: B, Min: C
  • c)
    Max: C, Min: D
  • d)
    Max: B, Min: D
  • e)
    Max: A, Min: D
Correct answer is option 'E'. Can you explain this answer?
Most Upvoted Answer
Set A: {-11, 0, 0, 11}Set B: {2, 4, 6, 8}Set C: {50, 51, 52, 53}Set D:...
To find the maximum and minimum standard deviation among the given sets, we need to calculate the standard deviation of each set and compare them.

Calculating Standard Deviation:

1. Set A: {-11, 0, 0, 11}
Mean = (-11+0+0+11)/4 = 0
Variance = [(0-(-11))^2 + (0-0)^2 + (0-0)^2 + (11-0)^2]/4
= [(121+0+0+121)]/4
= 60.5
Standard Deviation = √60.5 ≈ 7.78

2. Set B: {2, 4, 6, 8}
Mean = (2+4+6+8)/4 = 5
Variance = [(2-5)^2 + (4-5)^2 + (6-5)^2 + (8-5)^2]/4
= [9+1+1+9]/4
= 5
Standard Deviation = √5 ≈ 2.24

3. Set C: {50, 51, 52, 53}
Mean = (50+51+52+53)/4 = 51.5
Variance = [(50-51.5)^2 + (51-51.5)^2 + (52-51.5)^2 + (53-51.5)^2]/4
= [2.25+0.25+0.25+2.25]/4
= 1
Standard Deviation = √1 = 1

4. Set D: {12, 12, 12, 12}
Mean = (12+12+12+12)/4 = 12
Variance = [(12-12)^2 + (12-12)^2 + (12-12)^2 + (12-12)^2]/4
= 0
Standard Deviation = √0 = 0

Comparing Standard Deviations:

- The maximum standard deviation is in Set A, which is approximately 7.78.
- The minimum standard deviation is in Set D, which is 0.

Therefore, the correct answer is option E, which states that Set A has the maximum standard deviation and Set D has the minimum standard deviation.
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